How do you simplify $1 + 3 - (4 - 2)$ $1+3-(4-2)$ ?

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Answer 1 · 2015-04-22T19:53:37

$1 + 3 - (4 - 2)$ $1+3-(4-2)$

$= 1 + 3 - 2$ $=1+3-2$

$= 4 - 2$ $=4 - 2$

$= 2$ $=2$

Answer 2 · 2015-04-22T19:56:02

According to PEMDAS, you complete what's inside the parentheses first, then do the remaining addition and subtraction from left to right.

$1 + 3 - (4 - 2)$ $1+3-(4-2)$ =

$1 + 3 - 2$ $1+3-2$ =

$4 - 2$ $4-2$ = $2$ $2$

How do you simplify 1+3−(4−2)1+3-(4-2)?