How do you simplify #(1 + 3 times 3)^2 + 8# using order of operations?

2 Answers
Jun 21, 2018

Answer:

#108#

Explanation:

#(1+3*3)^2+8=10^2+8=108#

Answer:

108

Explanation:

given #(1+3*3)^2+8#, you first go inside the parenthesis (first you multiply and then add), so we get #(1+9)^2+8#.
now we add inside the parenthesis and we get #(10)^2 +8#.
now we have to calculate #(10)^2=(10)(10)=100#.
finally, we add the 8 and we obtain #100+8=108#