How do you simplify #10^a * 10^b * 10^c#?

1 Answer
May 13, 2016

Answer:

#10^a*10^b*10^c = 10^(a+b+c)#

Explanation:

This is easiest to see if #a, b, c# are positive integers:

#10^a*10^b*10^c#

#=overbrace(10xx10xx..xx10)^"a times" xx overbrace(10xx10xx..xx10)^"b times" xx overbrace(10xx10xx..xx10)^"c times"#

#=overbrace(10xx10xx..xx10)^"a + b + c times"#

#=10^(a+b+c)#

In fact, this works for any Real values of #a#, #b# and #c#.