How do you simplify #""_10P_8#?

1 Answer

#(10!)/(2!)=(10xx9xx8xx7xx6xx5xx4xx3xxcancel2)/cancel2=1,814,400#

Explanation:

The permutation general formula is:

#P_(n,k)=(n!)/((n-k)!); n="population", k="picks"#

and so the question is how to calculate:

#P_(10,8)=(10!)/((10-8)!)=(10!)/(2!)#

There are two ways to do it:

#(3,628,800)/2=1,814,400#

  • Or we can show the multiplications:

#(10xx9xx8xx7xx6xx5xx4xx3xxcancel2)/cancel2=1,814,400#