How do you simplify # 125v^2 = t#? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 2 Answers seol · Jacobi J. Jul 19, 2018 Answer: #v=\sqrt{t}/(5\sqrt5)# Explanation: Assuming you are solving for #v#: #125v^2=t# #(\cancel(125)v^2)/\cancel(125)=t/125# #v^2=t/125# #\sqrt{v^2}=\sqrt{t/125}# #v=\sqrt{t/(5*5*5)}=\sqrt{t}/\sqrt{25*5}=\sqrt{t}/(5\sqrt{5})# Hriman Jul 19, 2018 Answer: #v=+-sqrt(5t)/25# Explanation: To isolate #v#: #v^2=t/125# #v=+-sqrt(t/125)# #v= +-(sqrtt)/(5sqrt5)*sqrt5/sqrt5= +-sqrt(5t)/25# Related questions What are the different methods for solving quadratic equations? What would be the best method to solve #-3x^2+12x+1=0#? How do you solve #-4x^2+4x=9#? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation #81x^2+1=0#? How do you solve #-4x^2+4000x=0#? How do you solve for x in #x^2-6x+4=0#? How do you solve #x^2-6x-16=0# by factoring? How do you solve by factoring and using the principle of zero products #x^2 + 7x + 6 = 0#? How do you solve #x^2=2x#? See all questions in Comparing Methods for Solving Quadratics Impact of this question 319 views around the world You can reuse this answer Creative Commons License