# How do you simplify  12c^2d+3c(cd)-4d?

Jul 1, 2015

$12 {c}^{2} d + 3 c \left(c d\right) - 4 d = d \left(15 {c}^{2} - 4\right)$

#### Explanation:

$12 {c}^{2} d + 3 c \left(c d\right) - 4 d$
$\textcolor{w h i t e}{\text{XXXX}}$Multiply the middle term
$= 12 {c}^{2} d + 3 {c}^{d} - 4 d$
$\textcolor{w h i t e}{\text{XXXX}}$Combine the first two terms
$= 15 {c}^{2} d - 4 d$
$\textcolor{w h i t e}{\text{XXXX}}$Extract the common of $d$
$= d \left(15 {c}^{2} - 4\right)$