How do you simplify (12x^5y^3)/(4x^-1)?

$3 {x}^{6} {y}^{3}$
$\setminus \frac{12 {x}^{5} {y}^{3}}{4 {x}^{- 1}}$
$= \setminus \frac{12}{4} \left({x}^{5} {y}^{3} x\right)$
$= 3 {x}^{6} {y}^{3}$