# How do you simplify #(14a^2b + 35ab^2) / (7ab)#?

##### 1 Answer

May 7, 2015

All the terms in the numerator (i.e. on top) are divisible by the denominator

Taking it a little slower:

May 7, 2015

All the terms in the numerator (i.e. on top) are divisible by the denominator

Taking it a little slower:

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