How do you simplify #(15a^2b^2 )/(5ab)#? Algebra Rational Equations and Functions Division of Rational Expressions 2 Answers Alan P. May 3, 2015 #(15a^2b^2)/(5ab)# #= ((5ab)(3ab))/(5ab)# #= 3ab# Meave60 May 3, 2015 The answer is #3ab#. Simply #(15a^2b^2)/(5ab)# Divide 15 by 5. #15/5=3# Divide the exponents by subtracting the exponents in the denominator from the exponents in the numerator. #3a^((2-1))b^((2-1))# = #3ab# Related questions What is Division of Rational Expressions? How does the division of rational expressions differ from the multiplication of rational ... How do you divide 3 rational expressions? How do you divide rational expressions? How do you divide and simplify #\frac{9x^2-4}{2x-2} -: \frac{21x^2-2x-8}{1} #? How do you divide and reduce the expression to the lowest terms #2xy \-: \frac{2x^2}{y}#? How do you divide #\frac{x^2-25}{x+3} \-: (x-5)#? How do you divide #\frac{a^2+2ab+b^2}{ab^2-a^2b} \-: (a+b)#? How do you simplify #(w^2+6w+5)/(w+5)#? How do you simplify #(x^4-256)/(x-4)#? See all questions in Division of Rational Expressions Impact of this question 251 views around the world You can reuse this answer Creative Commons License