How do you simplify #(15a+5b)/(5ab) div 3a+b#?

1 Answer
Jul 14, 2015

Answer:

#(15a+5b)/(5ab) div (3a+b) = 1/(ab)#
#color(white)("XXXX")#Warning: this is not exactly what was asked, but I think it was what was intended.

Explanation:

#(15a+5b)/(5ab) div (3a+b)#

#color(white)("XXXX")##=(15a+5b)/(5ab) xx 1/(3a+b)#

#color(white)("XXXX")##= (5(3a+b))/(5(ab)) xx 1/(3a+b)#

#color(white)("XXXX")##= (cancel(5)(cancel(3a+b)))/(cancel(5)(ab)) xx 1/(cancel(3a+b))#

#color(white)("XXXX")##=1/(ab)#

Technically what was asked should have been evaluated as
#color(white)("XXXX")##((15a+5b)/(5ab) xx 1/(3a)) + 2#
Please repost, if that is what you intended.