How do you simplify #16^(-2/3)#?

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Answer 1 · 2015-03-30T14:59:20

#16^(-2/3)#

=#1/(16^(2/3))#

#= 1/((16^2)^1/3)#

#= root(3)(4xx4xx4xx4)#

#=1/(4 root(3)(4))#

#= ((root(3)(4))^2)/(4 (root(3)(4))^3)#

#= (root(3)(4^2))/16#

#= (2sqrt(2))/(16)#

#=sqrt(2)/8#