How do you simplify #(16x^2y)/(24xy^3) div (9xy)/(8x^2y^2)#?

1 Answer
Jul 13, 2015

Answer:

Dividing by a fraction is multiplying by its opposite. Then rewrite and cancel.

Explanation:

#=(16x^2y)/(24xy^3)*(8x^2y^2)/(9xy)#

#=(2*8*x*x*y)/(3*8*x*y*y*y)*(8*x*x*y*y)/(3*3*x*y)#

Now we cancel:

#=(2*cancel8*cancelx*x*cancely)/(3*cancel8*cancelx*cancely*y*y)*(8*cancelx*x*cancely*y)/(3*3*cancelx*cancely)#

And after working this out we can cancel one more #y#:

#=(2*8*x*x*cancely)/(3*3*3*y*cancely)=(16x^2)/(27y)#