How do you simplify #(2^0)^3 /( 2^3•3^3)#?

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Answer 1 · 2016-07-03T08:44:02

#1/216#

First step is to remove the brackets - multiply the indices.

#2^0/(2^3 xx 3^3) = 1/(2^3 xx 3^3)" (same result as " 1^3)#

In the denominator there are a few options - depending what is regarded as being 'simpler'.

We could simply leave it as it is, in index form with prime bases.

We could use the power form: 8 x 27, to get 216.

We could write it as #(2 xx 3)^3, "which gives 216" #

I prefer the third option - knowing the squares and cubes makes simplifying easier than having multiply.