# How do you simplify (2^3)^2 leaving only positive exponents?

Mar 20, 2016

#### Answer:

${2}^{6}$

#### Explanation:

Use the following rule:

${\left({x}^{a}\right)}^{b} = {x}^{a b}$

So, when we multiply $3$ and $2$, we get

${\left({2}^{3}\right)}^{2} = {2}^{3 \times 2} = {2}^{6}$

Note that this equals $64$, but the question referred specifically to use positive exponents.