# How do you simplify -(2/3)^4?

$- {\left(\frac{2}{3}\right)}^{4}$ $=$ $- \frac{16}{81}$
$- {\left(\frac{2}{3}\right)}^{4}$ $=$ $- 1 \times {\left(\frac{2}{3}\right)}^{4}$ $=$ $- 1 \times {2}^{4} / {3}^{4}$ $=$ $- 1 \times \frac{16}{81} = - \frac{16}{81}$.
Had the problem been written ${\left(- \frac{2}{3}\right)}^{4}$, the the answer would be $\frac{16}{81}$, but the brackets and the normal order of algebraic operations dictate a NEGATIVE answer.