How do you simplify #2^3 ÷ (7 ÷ 7 ÷ 8)# using order of operations?

1 Answer
Mar 11, 2018

Answer:

The final answer would be 64. We figure this out through the use of BIMDAS (Brackets, Indices, Multiplication/Division, Addition/Subtraction)

Explanation:

Begin with what is inside the brackets #(7-:7-:8)#. This will equal 0.125 or #1/8#. This will give us #2^3-:0.125#.

Next we deal with indices, which in this case is #2^3#. If we expand this we get #2*2*2# which will equal 8.

Now we are at #8-:0.125# or #8-:1/8#

This will produce a result of 64.