How do you simplify #(2/b)/(4/(b-3))#?
1 Answer
Jun 22, 2017
Explanation:
#"note that expressions of the form"#
#(a/b)/(c/d)=a/bxxd/c#
#rArr(2/b)/(4/(b-3))#
#=2/bxx(b-3)/4#
#=cancel(2)^1/b xx(b-3)/(cancel(4)^2#
#=(b-3)/(2b)#
