How do you simplify #2^(log_2(12)) #?

1 Answer
Mar 17, 2016

Answer:

#2^(log_2(12)) = 12#

Explanation:

By definition, the base-#a# log of a number #x# is the value #y# such that #a^y=x#. That is to say

#log_a(x) = y <=> a^y = x#

Then, applying the definition, for any #a#, we have #a^(log_a(x)) = x#

In this case, that gives us #2^(log_2(12)) = 12#