How do you simplify #27^(-2/3)#?
1 Answer
Jun 25, 2017
Explanation:
#"using the "color(blue)"laws of exponents"#
#color(red)(bar(ul(|color(white)(2/2)color(black)(a^-mhArr1/a^m ; a^(m/n)hArr(root(n)(a))^mcolor(white)(2/2)|)))#
#rArr27^(-2/3)=1/27^(2/3)=1/(root(3)(27))^2=1/3^2=1/9#
