How do you simplify #(2a^2- 3a-9) /( 8a^2+14+3) div(3a^2-7a-6)/(8a^2+14a+3)#?

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Answer 1 · 2018-05-14T22:25:45

#(2a+3)/(3a+2)#

When dividing fractions we turn the second fraction upside down and multiply

#(2a^2-3a-9)/(8a^2+14+3) xx (8a^2+14+3)/(3a^2-7a-6)#

The two equations cancel out to leave

#(2a^2-3a-9)/(3a^2-7a-6)#

Factorise

#((2a+3)(a-3))/((3a+2)(a-3))#

#(2a+3)/(3a+2)#