How do you simplify (2a^[2] b^[-3])^3/ (9a^[-3] b^[2]) ^-1/2?

1 Answer
May 19, 2015

Let's just bear in mind three important laws of exponents:

  • a^n/a^m=a^n-m

  • (a^n)^m=a^n*m

  • a^-n=1/a^n

Now, let's proceed:

(2^3*a^(2*3)b^((-3)*3))/(9^(-1)*a^((-3)(-1))*b^(2(-1)))/2

((2^3a^6b^-9)/(9^(-1)a^3b^-2))/2=((8a^3b^(-7))/(1/9))/2=(72a^3b^-7)/2=(36a^3)/b^7