How do you simplify $2e^(-2x)$ and $2e^(-x)$ ?

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Answer 1 · 2018-02-16T08:20:31

$2e^(-2x) = 2/e^(2x)" and "2e^(-x) = 2/e^x$

In a simplest form, the indices are not usually negative or zero.

Note the law of indices: $x^(-m) = 1/x^m$

So simplifying each of them separately would give:

$2e^(-2x) = 2/e^(2x)" and "2e^(-x) = 2/e^x$

How do you simplify 2e^(-2x)2e^(-2x) and 2e^(-x)2e^(-x)?