# How do you simplify 2e^(-2x) and 2e^(-x)?

Feb 16, 2018

$2 {e}^{- 2 x} = \frac{2}{e} ^ \left(2 x\right) \text{ and } 2 {e}^{- x} = \frac{2}{e} ^ x$

#### Explanation:

In a simplest form, the indices are not usually negative or zero.

Note the law of indices: ${x}^{- m} = \frac{1}{x} ^ m$

So simplifying each of them separately would give:

$2 {e}^{- 2 x} = \frac{2}{e} ^ \left(2 x\right) \text{ and } 2 {e}^{- x} = \frac{2}{e} ^ x$