# How do you simplify 2k^-1 and write it using only positive exponents?

${x}^{\textcolor{red}{a}} = \frac{1}{x} ^ \textcolor{red}{- a}$ and $a = {a}^{\textcolor{red}{1}}$
$2 {k}^{\textcolor{red}{- 1}} = \frac{2}{k} ^ \textcolor{red}{- - 1} = \frac{2}{k} ^ 1 = \frac{2}{k}$