# How do you simplify (2k^3*k^2)/k^-3 and write it using only positive exponents?

Apr 8, 2017

$= 2 {k}^{8}$

#### Explanation:

$\frac{2 {k}^{3} \cdot {k}^{2}}{k} ^ - 3$

$= \frac{2 {k}^{3} \cdot {k}^{2}}{\frac{1}{k} ^ 3}$

$= 2 {k}^{3} \cdot {k}^{2} \cdot {k}^{3}$

$= 2 {k}^{3 + 2 + 3}$