How do you simplify #(2p - 24)/(4p - 48)#?

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Answer 1 · 2015-05-30T13:26:01

Assuming #p!=12#

#(2p-24)/(4p-48)#

#= ((2)(p-12))/((4)(p-12))#

#= 2/4#

#=1/2#

Answer 2 · 2015-05-30T13:26:30

You can see that both numerator and denominator have their terms multiplied by a common factor, as follows:

#(2(p-12))/(4(p-12))#

As #(p-12)# is both in the numerator and in the denominator, we can cancel it

#(2cancel((p-12)))/(4cancel((p-12)))=2/4=color(green)(1/2)#