How do you simplify #(2x-10)/(25-x^2)# and what are the excluded values for the variables?

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Answer 1 · 2017-08-02T17:52:33

Given: #(2x-10)/(25-x^2)#

Factor out -2:

#(-2(x-5))/(x^2-25)#

Factor the denominator:

#(-2(x-5))/((x-5)(x+5))#

Please observe the canceled factors:

#(-2(cancel(x-5)))/((cancel(x-5))(x+5))#

Remove the canceled factors and append the excluded value:

#(-2)/(x+5); x!=-5#