# How do you simplify [(2x^3)^3 z^2] / (2z^4)?

You first get rid of the brackets. ${\left(2 {x}^{3}\right)}^{3} = {2}^{3} \cdot {x}^{3 \cdot 3}$
$= \frac{8 \cdot {x}^{9} \cdot {z}^{2}}{2 \cdot {z}^{4}} = \frac{\cancel{2} \cdot 4 \cdot {x}^{9} \cdot {\cancel{z}}^{2}}{\cancel{2} \cdot {\cancel{z}}^{2} \cdot {z}^{2}} = \frac{4 {x}^{9}}{z} ^ 2$