# How do you simplify (2x^3)^4?

May 3, 2016

I found: $16 {x}^{12}$
The power of $4$ is applied to all the elements inside your brackets so you get:
${\left(2 {x}^{3}\right)}^{4} = {2}^{4} {x}^{3 \cdot 4} = 16 {x}^{12}$
${\left({x}^{m}\right)}^{n} = {x}^{m \cdot n}$