Question

How do you simplify `(2x^3y^2)^2(2x^-1y^4)^3 / (2^1x^2y^-3)^-1`?

Answer 1

Expand the expression to get rid of the brackets, and then remove any common factors.

Explanation:

`(2x^3 y^2)^2` = `4x^6y^4`

`(2x^-1y^4)^3 = 8x^-3y^12`
`(2^1x^2y^-3)^-1` = `2^-1x^-2y^3`

`4x^6y^4*8x^-3y^12/(2^-1x^-2y^3)` = `32x^3y^16*2x^2y^-3`

= `64x^5y^13`