# How do you simplify (2x)^-4/(x^-1*x) and write it using only positive exponents?

Simplifying, the answer with positive exponents would be $\frac{1}{16 {x}^{4}}$
In the denominator, ${x}^{-} 1$ is simply $\frac{1}{x}$ and $\frac{1}{x} \cdot x = 1$, so the denominator simplifies to $1$.
Because the denominator is just $1$, all that is left to do is simplify the numerator, and ${\left(2 x\right)}^{-} 4 = \frac{1}{2 x} ^ 4 = \frac{1}{{2}^{4} \cdot {x}^{4}} = \frac{1}{16 {x}^{4}}$