Question

How do you simplify `(2x)^-4/(x^-1*x)` and write it using only positive exponents?

Answer 1

Simplifying, the answer with positive exponents would be `1/(16x^4)`

Explanation:

In the denominator, `x^-1` is simply `1/x` and `1/x * x = 1`, so the denominator simplifies to `1`.

Because the denominator is just `1`, all that is left to do is simplify the numerator, and `(2x)^-4 = 1/(2x)^4 = 1/(2^4 * x^4) = 1/(16x^4)`