# How do you simplify (-2x^4y^3)^3?

Feb 6, 2016

$- 8 {x}^{12} {y}^{9}$

#### Explanation:

using the following fact in relation to exponents

${\left({a}^{m}\right)}^{n} = {a}^{m n}$

now apply this to each of the factors

${\left(- 2 {x}^{4} {y}^{3}\right)}^{3} = {\left(- 2\right)}^{1 \times 3} . {x}^{4 \times 3} . {y}^{3 \times 3}$

$= {\left(- 2\right)}^{3.} {x}^{12.} {y}^{9} = - 8 {x}^{12} {y}^{9}$