# How do you simplify [(3^2)^4]^2?

Jun 1, 2017

$43 , 046 , 721$

#### Explanation:

We have: ${\left[{\left({3}^{2}\right)}^{4}\right]}^{2}$

Following BEDMAS rules, let's evaluate the terms within the parentheses first:

$= {\left[{\left(9\right)}^{4}\right]}^{2}$

$= {\left[6561\right]}^{2}$

$= 43 , 046 , 721$

${\left[{\left({3}^{2}\right)}^{4}\right]}^{2} = {3}^{2 \times 4 \times 2} = {3}^{16} = 43 , 046 , 721$
An alternate way to view this question is to remember that ${\left({x}^{a}\right)}^{b} = {x}^{a b}$, and so:
${\left[{\left({3}^{2}\right)}^{4}\right]}^{2} = {3}^{2 \times 4 \times 2} = {3}^{16} = 43 , 046 , 721$