# How do you simplify 3^-2?

Feb 21, 2016

$\textcolor{b l u e}{\frac{1}{9}}$

#### Explanation:

Since from the Law of Exponents (Negative Exponents)

${a}^{-} n = \frac{1}{a} ^ n$

Solving..

${3}^{-} 2 = \frac{1}{3} ^ 2$

${3}^{-} 2 = \frac{1}{9}$

or we can use the expanded form,

${3}^{-} 2 = \frac{\frac{1}{3}}{3}$

${3}^{2} = \frac{1}{3} \left(\frac{1}{3}\right)$

$= \frac{1}{9}$

:)