How do you simplify #(-3)^2times(-3)^4#?

1 Answer
Jan 17, 2016

Answer:

729

Explanation:

So according to the rules of exponents, two exponents being multiplied that have the same base are added together.
Let me break that down.

#A^B + A^C = A^(B+C)#

So, since #-3=-3#, we can do this:
#(-3)^2 + (-3)^4 = (-3)^(4+2) = (-3)^6#

And #(-3)^6 = #
#(-3) * (-3) * (-3) * (-3) * (-3) * (-3) = #
#9 * 9 * 9 = #
#81 * 9 = #
#729#