# How do you simplify (-3)^2times(-3)^4?

Jan 17, 2016

729

#### Explanation:

So according to the rules of exponents, two exponents being multiplied that have the same base are added together.
Let me break that down.

${A}^{B} + {A}^{C} = {A}^{B + C}$

So, since $- 3 = - 3$, we can do this:
${\left(- 3\right)}^{2} + {\left(- 3\right)}^{4} = {\left(- 3\right)}^{4 + 2} = {\left(- 3\right)}^{6}$

And ${\left(- 3\right)}^{6} =$
$\left(- 3\right) \cdot \left(- 3\right) \cdot \left(- 3\right) \cdot \left(- 3\right) \cdot \left(- 3\right) \cdot \left(- 3\right) =$
$9 \cdot 9 \cdot 9 =$
$81 \cdot 9 =$
$729$