# How do you simplify (3/7)^-2?

${\left(\frac{3}{7}\right)}^{-} 2 = {\left({\left(\frac{3}{7}\right)}^{2}\right)}^{-} 1 = {\left(\frac{{3}^{2}}{{7}^{2}}\right)}^{-} 1 = {\left(\frac{9}{49}\right)}^{-} 1 = \frac{49}{9}$
In general ${\left({x}^{a}\right)}^{b} = {x}^{a b}$ and ${\left(\frac{p}{q}\right)}^{-} 1 = \frac{q}{p}$.