Question

How do you simplify `[(3+i)x^2-ix+4+i]-[(-2+3i)x^2+(1-2i)x-3]`?

Answer 1

`[(3+i)x^2-ix+4+i]-[(-2+3i)x^2+(1-2i)x-3]=(5-2i)x^2+(-1+i)x+(7+i)`

Explanation:

`[(3+i)x^2-ix+4+i]-[(-2+3i)x^2+(1-2i)x-3]`

= `{(3+i)-(-2+3i)}x^2+{-i-(1-2i)}x+{4+i-(-3)]`

= `{3+i+2-3i}x^2+{-i-1+2i}x+{4+i+3]`

= `(5-2i)x^2+(-1+i)x+(7+i)`