# How do you simplify 3/(x+2) - 2/(x^2+x-2) + 2/(x-1) ?

Get a common denominator and add to get $\frac{5 x - 1}{{x}^{2} + x - 2}$
Since ${x}^{2} + x - 2 = \left(x + 2\right) \left(x - 1\right)$, the common denominator is $\left(x + 2\right) \left(x - 1\right)$:
$\frac{3}{x + 2} - \frac{2}{\left(x + 2\right) \left(x - 1\right)} + \frac{2}{x - 1} = \frac{3 \left(x - 1\right) - 2 + 2 \left(x + 2\right)}{\left(x + 2\right) \left(x - 1\right)}$
$= \frac{3 x - 3 - 2 + 2 x + 4}{\left(x + 2\right) \left(x - 1\right)} = \frac{5 x - 1}{\left(x + 2\right) \left(x - 1\right)} = \frac{5 x - 1}{{x}^{2} + x - 2}$