# How do you simplify 3/(x+5 )- 2/(x-3)?

$\frac{x - 19}{{x}^{2} + 2 x - 15}$
above equation could be like this $\frac{3 \left(x - 3\right) - 2 \left(x + 5\right)}{\left(x + 5\right) \left(x - 3\right)}$ and this is equal to $\frac{x - 19}{{x}^{2} + 2 x - 15}$
so the answer is $\frac{x - 19}{{x}^{2} + 2 x - 15}$ if you want to know x about $\frac{x - 19}{{x}^{2} + 2 x - 15} = 0$ the x could 19 but not -5 or 3 because denominator can't be zero