How do you simplify $(-32)^(-3/5)$ ?

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Answer 1 · 2016-10-13T14:45:15

$= 1/(-8)$

There are two laws of indices in place here.

$x^-m = 1/x^m" and "x^(p/q) = (rootq(x))^p$

Use the sign law first to make the index positive.

$1/((-32)^(3/5)$

Change the index to a root and a power:

$=1/color(red)(root5((-32)))^(3)" "larr$ find 5th root of -32

$= 1/((-2)^3)" "larr$ find the cube of -2

$= 1/(-8)$

How do you simplify (-32)^(-3/5)(-32)^(-3/5)?