How do you simplify #(36mn^3)/(24m^2n^5)#?

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Answer 1 · 2015-05-27T19:48:04

Answer: #3/(2mn^2)#

Working:

First, simplify #36/24#:

Divide both the numerator and the denominator by 12 :
#=3/2#

Rule : We know that #m^(x)-:m^(y)=m^(x-y)#

So;

#3/2m^[(1-2)]n^[(3-5)]=3/2m^(-1)n^(-2)#

= #3/(2mn^2)#