How do you simplify #(39t^4uv^-2)/(13t^-3u^7)#?

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Answer 1 · 2017-05-23T07:17:05

Follow explanation. #(13*t^7)/(v^2*u^6)#

39 is 3 times larger than 13.

#39/13=3#

Now the alphabetic terms can be written as

#(t^4*t^3*u)/(v^2*u*u^6)#

When you simplify the above terms:

#t^7/(v^2*u^6)# is obtained

Therefore your final answer is

#(13*t^7)/(v^2*u^6)#

This is your answer #(13*t^7)/(v^2*u^6)#