# How do you simplify (39t^4uv^-2)/(13t^-3u^7)?

May 23, 2017

Follow explanation. $\frac{13 \cdot {t}^{7}}{{v}^{2} \cdot {u}^{6}}$

#### Explanation:

39 is 3 times larger than 13.

$\frac{39}{13} = 3$

Now the alphabetic terms can be written as

$\frac{{t}^{4} \cdot {t}^{3} \cdot u}{{v}^{2} \cdot u \cdot {u}^{6}}$

When you simplify the above terms:

${t}^{7} / \left({v}^{2} \cdot {u}^{6}\right)$ is obtained

$\frac{13 \cdot {t}^{7}}{{v}^{2} \cdot {u}^{6}}$
This is your answer $\frac{13 \cdot {t}^{7}}{{v}^{2} \cdot {u}^{6}}$