# How do you simplify (3a^4-2a^2+5a-10)-(2a^4+4a^2+5a-2)?

Sep 10, 2015

The simplify form of
$\left(3 {a}^{4} - 2 {a}^{2} + 5 a - 10\right)$ - $\left(2 {a}^{4} + 4 {a}^{2} + 5 a - 2\right)$

is ${a}^{4} - 6 {a}^{2} - 8$

#### Explanation:

In order to simplify
$\left(3 {a}^{4} - 2 {a}^{2} + 5 a - 10\right)$ - $\left(2 {a}^{4} + 4 {a}^{2} + 5 a - 2\right)$, you must

distribute the negative to all of $\left(2 {a}^{4} + 4 {a}^{2} + 5 a - 2\right)$

so - $\left(2 {a}^{4} + 4 {a}^{2} + 5 a - 2\right)$ is equal to -$2 {a}^{4} - 4 {a}^{2} - 5 a + 2$

now you take

$3 {a}^{4} - 2 {a}^{2} + 5 a - 10$
-$2 {a}^{4} - 4 {a}^{2} - 5 a + 2$

= ${a}^{4} - 6 {a}^{2} - 8$