How do you simplify (3a^4b^2)^3(3a4b2)3?

1 Answer
Oct 24, 2017

27a^12b^627a12b6

Explanation:

Move the 33 inside by simply multiplying every power by 33.

(3a^4b^2)^3 = (3^1a^4b^2)^3(3a4b2)3=(31a4b2)3

= (3^(1xx3)a^(4xx3)b^(2xx3))=(31×3a4×3b2×3)

= 3^3a^12b^6=33a12b6

You can calculate 3^333 straight away, because

3^3 = 3xx3xx3 = (3xx3)xx3 = 9xx3 = 2733=3×3×3=(3×3)×3=9×3=27

so

(3a^4b^2)^3 = 27a^12b^6(3a4b2)3=27a12b6