How do you simplify $3 a + b - 6 (a - 2 b)$ $3a+b-6(a-2b)$ ?

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Answer 1 · 2017-05-11T14:43:38

You can distribute $- 6$ $-6$ into $(a - 2 b)$ $(a - 2b)$ , then proceed with the simplifying operations.

$- 3 a + 13 b$ $-3a + 13b$ .

$3 a + b - 6 (a - 2 b)$ $3a+b-6(a-2b)" "$ Using the distributive property, you will get :

$- 6 (a - 2 b) = - 6 a + 12 b$ $-6(a-2b) =-6a + 12b$ .

So in total, you have $3 a + b - 6 a + 12 b$ $3a +b -6a+12b$ , right?

Do the necessary simplifying and you'll get

$- 3 a + 13 b$ $-3a + 13b$ .

How do you simplify 3a+b-6(a-2b)3a+b−6(a−2b)3a+b-6(a-2b)?