How do you simplify ((3t^6u^2v^5)/(9tuv^21))^0?

The answer is $1$.
${\left(\frac{3 {t}^{6} {u}^{2} {v}^{5}}{9 t u {v}^{21}}\right)}^{0}$
The answer is $1$. Any number raised to the zero power is $1$. ${x}^{0} = 1$