How do you simplify $(3x-12)/(x²-3x-18)- ( x-4)/(x-6)^2$ ?

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Answer 1 · 2018-03-31T18:47:26

$[(x-4)(2x-21)]/[(x+3)(x-6)^2]$

$(3x-12)/(x^2-3x-18)-(x-4)/(x-6)^2$

= $(3*(x-4))/((x+3)*(x-6))-(x-4)/(x-6)^2$

= $(x-4)/(x-6)*[3/(x+3)-1/(x-6)]$

= $(x-4)/(x-6)*[3(x-6)-(x+3)]/[(x+3)(x-6)]$

= $[(x-4)(2x-21)]/[(x+3)(x-6)^2]$

How do you simplify (3x-12)/(x²-3x-18)- ( x-4)/(x-6)^2(3x-12)/(x²-3x-18)- ( x-4)/(x-6)^2?