# How do you simplify (3x^2+17x-6)/(x^3-36x)?

Sep 24, 2015

$\frac{3 {x}^{2} + 17 x - 6}{{x}^{3} - 36 x} = \frac{3 x - 1}{x \left(x - 6\right)}$

#### Explanation:

First of all you are going to need to factorise both numerator and denominator.

$\frac{3 {x}^{2} + 17 x - 6}{{x}^{3} - 36 x} = \frac{\left(3 x - 1\right) \left(x + 6\right)}{x \left(x - 6\right) \left(x + 6\right)}$

Then you will be able to cancel out the common factor of x+6 which yields:

$\frac{3 {x}^{2} + 17 x - 6}{{x}^{3} - 36 x} = \frac{3 x - 1}{x \left(x - 6\right)}$