How do you simplify #(3x^-2y^2)/(6xy^2)#?

1 Answer
Aug 5, 2016

Answer:

#1/(2x^3)#

Explanation:

Using the #color(blue)"laws of exponents"#

#color(orange)"Reminder"#

#color(red)(|bar(ul(color(white)(a/a)color(black)(a^nxxa^m=a^(n+m)" and " a^-mhArr1/a^m)color(white)(a/a)|)))#

#rArr(3x^-2y^2)/(6xy^2)" can be expressed as"#

#3/6xxx^-2/x xxy^2/y^2#

#=cancel(3)^1/(cancel(6)^2)xx1/x^(1+2)xx(cancel(y^2)^1)/cancel(y2)^1#

#=1/2xx1/x^3xx1=(1xx1xx1)/(2xxx^3xx1)=1/(2x^3)#