# How do you simplify (3x^-4y^3)^2?

$9 {x}^{-} 8 {y}^{6}$ or $\frac{9 {y}^{6}}{x} ^ 8$
${3}^{1 \cdot 2} {x}^{- 4 \cdot 2} {y}^{3 \cdot 2} \to {3}^{2} {x}^{-} 8 {y}^{6} \to 9 {x}^{-} 8 {y}^{6}$