How do you simplify #(3x)/(6x^2) times (2y-6)/(y-3)#? Algebra Rational Equations and Functions Multiplication of Rational Expressions 1 Answer Konstantinos Michailidis May 26, 2016 It is #(3x)/(6x^2) times (2y-6)/(y-3)=(3x)/(2x*3x) times ((2*(y-3))/(y-3))= (cancel(3x))/(2x*cancel(3x)) times ((2*cancel(y-3))/cancel(y-3))= 1/(2x) times 2=1/(cancel2*x)*cancel2=1/x# Answer link Related questions What is Multiplication of Rational Expressions? How do you multiplying rational expressions? Is multiplication of rational expressions commutative? How do you multiply #\frac{12x^2-x-6}{x^2-1} \cdot \frac{x^2+7x+6}{4x^2-27x+18}#? How do you multiply and simplify to the lowest terms #\frac{x^3}{2y^3} \cdot \frac{2y^2}{x}#? How do you multiply #\frac{5x^2+16x+3}{36x^2-25} \cdot (6x^2+5x)#? How do you multiply and simplify the expression #2xy \cdot \frac{2y^2}{x^3}#? How do you multiply #(a^2-a-12)/(a^2-5a+4)*(a^2+2a-3)/(a^2+a-6)#? How do you multiply #(4(x+2))/(5x)*(6x^2)/(2x)#? How do you multiply #(30a^2)/(18b)*(6b)/(5a)#? See all questions in Multiplication of Rational Expressions Impact of this question 2357 views around the world You can reuse this answer Creative Commons License